007-valid-date.sh

#!/bin/sh
# valid-date - validate date, taking into account leap year rules

normdate="./003-normdate.sh"	 # hack #3 for normalizing month name

exceedsDaysInMonth()
{
  # given a month name, return 0 if the specified day value is
  # less than or equal to the max days in the month, 1 otherwise

  case $(echo $1|tr '[:upper:]' '[:lower:]') in
    jan* ) days=31    ;;  feb* ) days=28    ;;
    mar* ) days=31    ;;  apr* ) days=30    ;;
    may* ) days=31    ;;  jun* ) days=30    ;;
    jul* ) days=31    ;;  aug* ) days=31    ;;
    sep* ) days=30    ;;  oct* ) days=31    ;;
    nov* ) days=30    ;;  dec* ) days=31    ;;
    * ) echo "$0: Unknown month name $1" >&2; exit 1
   esac
   
   if [ $2 -lt 1 -o $2 -gt $days ] ; then
     return 1
   else
     return 0	# all is well
   fi 
}

isLeapYear()
{    
  # this function returns 0 if a leap year, 1 otherwise
  # The formula for checking whether a year is a leap year is: 
  # 1. years divisible by four are leap years, unless..
  # 2. years also divisible by 100 are not leap years, except...
  # 3. years divisible by 400 are leap years

  year=$1
  if [ "$((year % 4))" -ne 0 ] ; then
    return 1 # nope, not a leap year
  elif [ "$((year % 400))" -eq 0 ] ; then
    return 0 # yes, it's a leap year
  elif [ "$((year % 100))" -eq 0 ] ; then
    return 1
  else
    return 0
  fi 
}

## Begin main script

if [ $# -ne 3 ] ; then
  echo "Usage: $0 month day year" >&2
  echo "Typical input formats are August 3 1962 and 8 3 2002" >&2
  exit 1
fi

# normalize date and split back out returned values

newdate="$($normdate "$@")"

if [ $? -eq 1 ] ; then
  exit 1	# error condition already reported by normdate
fi

month="$(echo $newdate | cut -d\  -f1)"
  day="$(echo $newdate | cut -d\  -f2)"
 year="$(echo $newdate | cut -d\  -f3)"

# Now that we have a normalized date, let's check to see if the
# day value is logical 

if ! exceedsDaysInMonth $month "$2" ; then
  if [ "$month" = "Feb" -a $2 -eq 29 ] ; then
    if ! isLeapYear $3 ; then
      echo "$0: $3 is not a leap year, so Feb doesn't have 29 days" >&2
      exit 1
    fi
  else 
    echo "$0: bad day value: $month doesn't have $2 days" >&2
    exit 1
  fi
fi

echo "Valid date: $newdate"

exit 0